Question

Three consecutive even integers have a sum of 24 . Find the integers

Answer 1

Answer:

6, 8, 10

Step-by-step explanation:

Let n be the first integer.

Since they are consecutive even integers, the other two are n+2 and n+4.

Their sum is 24 so

n + ( n + 2 ) + ( n + 4 ) = 24

=> 3n + 6 = 24

=> 3n = 18

=> n = 6

So the integers in question are 6, 8, 10

Answer 2

Answer:

Step-by-step explanation:

Let the integers be x,x+1 and x+2(as they are consecutive)

x+x+1+x+2=24

3x+3=24

3x=21

x=7

There the integers are,

x=7

x+1=8

And x+2=9