Math, asked by monster7133, 1 year ago

Three consecutive even integers have a sum of 24 . Find the integers

Answers

Answered by Anonymous

Answer:

6, 8, 10

Step-by-step explanation:

Let n be the first integer.

Since they are consecutive even integers, the other two are n+2 and n+4.

Their sum is 24 so

n + ( n + 2 ) + ( n + 4 ) = 24

=> 3n + 6 = 24

=> 3n = 18

=> n = 6

So the integers in question are 6, 8, 10

Anonymous: hope this helps. plzzz mark it brainliest! all the best!!!!!!

keyasingh17: Wrong

keyasingh17: The third one would be n+3

keyasingh17: 6,8,10 are not even consecutive

Anonymous: the problem refers to "consecutive even integers". The even integers are ..., -2, 0, 2, 4, 6, 8, ... In the list of *even integers", the numbers 6, 8 and 10 are morest definitely consecutive!!!

keyasingh17: Oh

Answered by keyasingh17

Answer:

Step-by-step explanation:

Let the integers be x,x+1 and x+2(as they are consecutive)

x+x+1+x+2=24

3x+3=24

3x=21

x=7

There the integers are,

x=7

x+1=8

And x+2=9

Anonymous: 7 and 9 are not *even*

keyasingh17: Sorry

Anonymous: It's nothing. Happy problem-solving!!!!

keyasingh17: Yeah

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