Three consecutive even integers have a sum of 42
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let one =x
another =x+2
third =x+4
ACCORDING TO THE QUESTION,
x+x+2+x+4=42
3x+6=42
3x=42-6
3x=36
x=12
x+2=14
x+4=16
another =x+2
third =x+4
ACCORDING TO THE QUESTION,
x+x+2+x+4=42
3x+6=42
3x=42-6
3x=36
x=12
x+2=14
x+4=16
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