Question

Three consecutive even integers have a sum of 48 Find the integers.

Answer 1

x + (x+1) + (x+2) = 48

3x +3 = 48

3x = 48-3 (45)

x= 45/3 = 15

Therefore the integers are 15 16 and 17

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Answer 2

Let the integers be x, x + 2 and x + 4

A/q,  

x + x + 2 + x + 4 = 48  

3x + 6 = 48

3x =  48 - 6

x =  42

x = $\frac{42}{3}$  

x =  14

1st number => x => 14

 2nd number => x + 2 => 14 + 2 => 16

3rd number => x + 4 => 14 + 4 => 18