Three consecutive EVEN integers have a sum of 60. Find the integers.
Answers
Step-by-step explanation:
The sum of 3 consecutive even numbers is 60. What is the smallest of them?
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Let 2n = the smallest consecutive even number.
Let 2(n + 1) = 2n + 2 = the next consecutive even number, and ...
Let 2(n + 2) = 2n + 4 = the third consecutive even number.
Since the sum of these 3 consecutive even numbers is 60, we can write the following equation:
2n + (2n + 2) + (2n + 4) = 60
2n + 2n + 2 + 2n + 4 = 60
By the Commutative Property of Addition, i.e., a + b = b + a, we have on the left side of the equation:
2n + 2n + 2n + 2 + 4 = 60
Now, collecting like-terms on the left side, we get:
(2 + 2 + 2)n + 6 = 60
(6)n + 6 = 60
6n + 6 = 60
Now, in order to solve for n, we begin isolating n on the
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The sum of three consecutive even numbers is 168. What is the smallest of the three numbers?
Answer: 18
Algebra:
Let 2n denote the smallest even number of the 3 consecutive numbers where n is an integer to be determined. Then the next two consecutive even numbers are 2n+2 and 2n+4. Therefore, the sum of the 3 consecutive numbers is 2n + 2n+2 +2n+4 = 6n + 6 and this sum is equal to 60 by hypothesis. So we write,
6n + 6 = 60 Dividing through by 6,
n + 1 = 10 Transposing 1 from LHS to right-side,
n = 10 - 1 = 9
Therefore the smallest even number
2n = 18
and the three consecutive numbers are
18, 20, 22
It is easily seen that the sum of the three consecutive numbers so found is
18 + 20 + 22 = 60 (Ver
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Let the 3 consecutive even numbers be x, x+2 and x+4.
Thus, x+x+2+x+4=60 = 3x+6=60 = 3x=60-6
= 3x=54.
As 3x=54,
Therefore, x=54/3 = x=18.
As ‘x’ is the smallest number in the series, therefore the smallest number is 18.
Thus, the next 2 consecutive even numbers should be 20 and 22.
Let's verify:-
18+20+22=60. Thus, this expression satisfies the statement that “ The sum of 3 consecutive even numbers is 60.”
We can see that the smallest number is 18.
Thus, the answer to our question is ‘18’.
Answer:
let the three consecutive even numbers be x x+2 and x+4
thus , x x+2x+4=60
=3x+6=60
3x=60-6
3x=54
there for x=54/3 =x=16
as x is the smallest no. in the series
therefore the smallest no. is 18
thus the next two consecutive no. in the series is 20and 22