Question

Three consecutive even number are such that 5 times the second number exceeds four times the third number by 18 the second no is

Answer 1

${{\underline{\underline{{\textsf{\textbf{Answer : }}}}}}}$

The second number is 5 ☑

${{\underline{\underline{{\textsf{\textbf{Explanation : }}}}}}}$

Given statement,

➡ Three consecutive even numbers that 5 times the 2nd number exceeds 4 times the 3rd number by 18.

• As they are even consecutive.

❐ Step 1:

Assuming,

➔ 1st number = x

➔ 2nd number = (x + 2)

➔ 3rd number = (x + 4)

❐ Step 2:

5 times the 2nd number i. e., 5(x + 2) exceeds the third number i. e., (x + 4) by 18.

Equation formed :

➙ 5(x + 2) - 18 = (x + 4)

❐ Step 3:

〄 According to the question :

➙ 5(x + 2) - 18 = (x + 4)

➙ 5x + 10 - 18 = x + 4

➙ 5x - 8 = x + 4

➙ 5x - x = 4 + 8

➙ 4x = 12

➙ x = $\bf\frac{12}{4}$

➙ x = 3

${{\underline{\underline{{\textsf{\textbf{Hence, }}}}}}}$

The second number is :

= (x + 2)

= 3 + 2

= 5 ans. ☑