Math, asked by ushachiki, 9 hours ago

three consecutive even numberare such that the largest of them is twice the smallest. find the second largest number among the three.​

Answers

Answered by datars211gmilcom
4

Answer:

your answer is given in the above photo

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Answered by Yuseong
24

Answer :

6

_______________

As per the provided information in the given question, we have :

  • Three consecutive even numbers are such that the largest of them is twice the smallest.

We are asked to calculate,

  • The second largest number among the three.

In order to calculate the second largest number among the three, we need to calculate those consecutive numbers.

Let us assume the first even number as x. So, the next two consecutive numbers would be (x + 2) and (x + 4).

Now, according to the question,

~The largest of them is twice the smallest.

Here,

⇒ Largest number = (x + 4)

⇒ Smallest number = x

Writing it in the form of an equation,

 \longmapsto \rm {(x +4) = 2x } \\

Removing the brackets.

 \longmapsto \rm {x +4= 2x } \\

Transposing x from L.H.S to R.H.S.

 \longmapsto \rm {4= 2x-x } \\

Performing substraction.

 \longmapsto \bf {4= x } \\

Therefore,

 \longmapsto \bf {First \; Number= 4 } \\

And,

 \longmapsto \rm {Second \; Number = (x +2) } \\

Substituting the value of x.

 \longmapsto \rm {Second \; Number = (4 +2) } \\

 \longmapsto \bf {Second \; Number = 6 } \\

And,

 \longmapsto \rm {Third \; Number = (x +4) } \\

Substituting the value of x.

 \longmapsto \rm {Third \; Number = (4 +4) } \\

 \longmapsto \bf {Third \; Number = 8 } \\

Here,

⇒ Second largest number = 6

∴ 6 is the second largest number among three.

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