Question

three consecutive even numbers whose sum is 66​

Answer 1

Answer:

20,22,24

Step-by-step explanation:

If the second number is

n , then the first is

n−2and the third n+2, so we have:66

=(n−2)+n+(n+2)

=3n

Dividing both ends by 3, we find n

=22.

So the three numbers are: 20,22,24.

The smallest of these is 20.

Answer 2

the answer is given in the attachment above