Question

Three consecutive integer are such that when they are taken in increasing order and multiplied by 2,3,and 4 respectively, they add upto 74.find these numbers​

Answer 1

Answer:

3 consecutive nos are 7,8 &9

Step-by-step explanation:

let the nos be x, x+1 & x+2

according to the given condition:

2x+3(x+1)+4(x+2)=74

2x+3x+3+4x+8=74

9x+11=74

9x=63

x=7

x+1=8

x+2=9

Answer 2

Answer:

Answer:Three consecutive integers are 7,8 and 9

Solution:

Let the numbers are x, x+1 and x+2

(Since these are consecutive integers)

they are taken in increasing order and multiplied by 2,3 and 4 respectively

So x becomes 2x

(x+1) becomes 3(x+1)

(x+2) becomes 4(x+2)

they add up to 74, so ATQ

2x +3x+3 +4x+8 =74

9x+11 = 74

9x =74-11      

x = 63/9

x = 7

x=7

x+1 = 8

x+2 = 9

So,

Integers are 7, 8, and 9