three consecutive integer are such that when they are taken in increasing order and multiplied by 2,3and4respectively they add up-to 74 find these numbers answer plz
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The required numbers are 7 8 and 9
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Let the numbers be x , x+1,x+2
Then the no. multiplied by 2,3 and 4 would be 2x ,3x+3 and 4x+8
Now,
2x +3x+3+4x+8=74
9x+ 11= 74
9x=63
x=7
So the no. are
x=7
x+1=8
and x+2=9
Then the no. multiplied by 2,3 and 4 would be 2x ,3x+3 and 4x+8
Now,
2x +3x+3+4x+8=74
9x+ 11= 74
9x=63
x=7
So the no. are
x=7
x+1=8
and x+2=9
Similar questions
Multiplying it by 2, 3 and 4 respectively, we get,
2(x) = 2x
3(x+1) =3x +3
4(x+2) = 4x + 8
Forming the equation, we get,
2x+ 3x+3 + 4x +8 = 74(As the consecutive no.s add up to 74)
9x + 11 = 74
9x = 74 -11
9x = 63
x = 63/9 = 7
x =7
Therefore the no.s are 7(x), 8(x+1) and 9(x+2).
Hope this helps!!!!!!