Question

three consecutive integer are such that when they are taken in increasing order and multiplied by 2,3and 4respectivly, they add up to 137 find the number​

Answer 1

Answer:

yoo!! bro ✌✌

Your answer:-

let the three consecutive numbers be x, x + 1 and x + 2.

Now, in your question it's said that they are taken in increasing order and multiplied by 2,3 and 4 respectively.

so, 2(x) + 3( x + 1 ) + 4( x + 2 ).

= 2x + 3x + 3 + 4x + 8 = 137. ( it is mentioned that they add upto 137 ).

= 9x + 11 = 137. ( adding all the like terms ).

= 9x = 137 - 11

= 9x = 126

= x = 126/9

= x = 14.

Therefore, our first integer is 14.

our second integer is x + 1 = 14 + 1 = 15.

our third integer is x + 2 = 14 + 2 = 16.

so, your consecutive integers are 14, 15 and 16.