Question

Three consecutive integer is 36 find the numbers

Answer 1

0
Let the largest integer be n. Since they are consecutive integers the other two integers would be (n - 2) and (n - 1).

The sum of these integers are (n - 2) + (n - 1) + n = 3n -3 = 36.

Then n = (36 +3)/3 = 13
The consecutive integers are 11, 12, 13

Answer 2

Hello !

Here is your answer

consecutive integers so

x+x+1+x+2 = 36

3x + 3 = 36

3x = 33

x= 33/3 = 11

The nos. are 11 , 12 , 13