Question

Three consecutive integeres add up to 51 . What are these integeres ??

Answer 1

Answer:

Let the first number be x

2nd number=x+1

3rd number=x+2

A/q

x+x+1+x+2=51

3x+3=51

3x=51-3

3x=48

x=48÷3

x=16

Then,

x+1=16+1=17

x+2=16+2=18.