three consecutive integers add up 251 what are these integers
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There is a minor mistake in your question. The sum should be 252 and not 251.
Let the common multiple be x
So, let the 1st integer be x, 2nd be x + 1 and 3rd be x + 2
Their sum is 251
According to the given condition
x + x + 1 + x + 2 = 252
∴ 3x + 3 = 252
∴ 3x = 252 - 3
∴ 3x = 248
∴ x =
∴ x = 83
∴ 1st integer ➾ x
➾
∴ 2nd integer ➾ x + 1
➾ 83 + 1
➾
∴ 3rd integer ➾ x + 2
➾ 83 + 2
➾
Let the common multiple be x
So, let the 1st integer be x, 2nd be x + 1 and 3rd be x + 2
Their sum is 251
According to the given condition
x + x + 1 + x + 2 = 252
∴ 3x + 3 = 252
∴ 3x = 252 - 3
∴ 3x = 248
∴ x =
∴ x = 83
∴ 1st integer ➾ x
➾
∴ 2nd integer ➾ x + 1
➾ 83 + 1
➾
∴ 3rd integer ➾ x + 2
➾ 83 + 2
➾
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