Question

Three consecutive integers add up to 36. What is the smallest of the three integers?
Let x = 1st integer
x+1 = 2nd integer
x+2 = 3rd integer
Which is the correct equation?

3x+3=36

2x+3=36

x+x+1+x+2=36

3x+6=36​

Answer 1

Step-by-step explanation:

Let your 1st integer be called "n", then the 2nd will be n+1, and the 3rd will be n+2. Then n+1 = -12 and n+2 = -11. where -13 is the smallest.

Answer 2

Answer:

the first and third eq are the same

Step-by-step explanation:

smallest integer is

3x+3=36

3x= 33

x=11

hence the numbers are...11;12;13