Question

Three consecutive integers add up to 39. What are these integers.​

Answer 1

$\boxed{ \underline{\underline{ \Rsh\tt \purple{Solution : - }}} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize\tt{Let \: three \: consecutive \: integers \: are :- }$

$</strong><strong>\footnotesize\tt</strong><strong>{</strong><strong> (x), \: (x+1) \: ,(x+2)</strong><strong>\:</strong><strong>}</strong><strong>$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize\tt\purple{According \: to \: question:-}</p><p>$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\purple\Rsh\footnotesize\tt{(x)+(x+1)+(x+2) = 39}$

$\purple\Rsh\footnotesize\tt{x + x+x + 1 + 2= 39}$

$\purple\Rsh\footnotesize\tt{3x + 3= 39}$

$\purple\Rsh\footnotesize\tt{3x = 39 - 3}$

$\purple\Rsh\footnotesize\tt{3x = 36}$

$\purple\Rsh\footnotesize\tt{x = } \tt{ \: \frac{36}{3} }$

$\purple\Rsh\footnotesize\tt{x = } \tt{ \: \cancel \frac{36}{3} }$

$\boxed{ \underline{\underline{\purple\Rsh\footnotesize\tt{x = } \tt{ \: 12 }}} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\purple\Rsh\footnotesize\tt{x + 1 = \: } \tt{12 + 1 }$

$\boxed{ \underline{\underline{\purple\Rsh\footnotesize\tt{x + 1 = } \tt{ \: 13}}} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\purple\Rsh\footnotesize\tt{x + 2 = \: } \tt{12 + 2 }$

$\boxed{ \underline{\underline{\purple\Rsh\footnotesize\tt{x + 2 = } \tt{ \: 14}}} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\footnotesize\tt{Three \: consecutive \: integers \: are \:} \footnotesize\tt \purple{12 \:, 13 \: and \: 14}$

Answer 2

Given :

• the three consecutive integers add up = 39.

To find :

• the integers

Solution :

⇒ Let's find the integers.

→ (x + 1) + (x + 2) + (x + 3) = 39

→ (x + x + x) + (1 + 2 + 3) = 39

→ (3x + 6) = 39

→ 3x + 6 = 39

→ 3x = 39 - 6

→ 3x = 33

→ x = 33/3

→ x = 11

→ (x + 1)

= (11 + 1)

= 12

→ (x + 2)

= (11 + 2

= 13

→ (x + 3)

= 11 + 3

= 14

• Therefore, the integers are 12, 13 and 14.