Question

Three consecutive integers add up to 48. What are these integers?​

Answer 1

Answer :-

The three consecutive integers are 15, 16 and 17.

Step-by-step explanation:

To Find :-

• The integers.

Given that,

• The sum of three consecutive integers are 48.

Assumption :-

Let us assume the three integers as (x), (x + 1) and (x + 2).

∴ Also given,

• (x) + (x + 1) + (x + 2) = 48

⇒ (x) + (x + 1) + (x + 2) = 48

⇒ x + x + 1 + x + 2 = 48

⇒ x + x + x + 1 + 2 = 48

⇒ 3x + 1 + 2 = 48

⇒ 3x + 3 = 48

⇒ 3x = 48 - 3

⇒ 3x = 45

⇒ x = 45/3

⇒ x = 15

The value of x is 15.

Now, the integers are :-

• (x) = 15
• (x + 1) = (15 + 1) = 16
• (x + 2) = (15 + 2) = 17

Hence, The integers are 15, 16 and 17.

V E R I F I C A T I O N :-

• (x) + (x + 1) + (x + 2) = 48

Putting the value of integers, on L.H.S

We got,

• (x) = 15
• (x + 1) = 16
• (x + 2) = 17

⇒ (x) + (x + 1) + (x + 2)

⇒ 15 + 16 + 17

⇒ 31 + 17

⇒ 48

Now, L.H.S = R.H.S = 48.

Hence, Verified!

Answer 2

15,16and 17

Step-by-step explanation:

x+1+x+2+x+3=48

=>3x+6=48

=>3x=48-6

=>3x=42

=>x=42/3=14

first no = 15

second no=16

third no= 17

hope it helps u