Question

three consecutive integers add up-to 51.if they differ by 18, what are the numbers​

Answer 1

16,17 and 18.

let three succesive number are x,x+1 and x+2.

so x+(x+1)+(x+2)=51

3x + 3=51

3x=48

x=16

so three succesive number are 16,17 and 18.

PLEASE MARK IT AS THE BRAINLIEST

Answer 2

Answer:

-1,17,35

Step-by-step explanation:

let us assume the first integer be x then second integer will be x+18 as the difference between them is 18,the third integer will be second integer+18 i.e x+18+18 i.e, x+36

they add up to 51

x+x+18+x+36+51

3x+54=51

x= -3/3

x=-1

substitute x value in 3 integers..

x= -1

second integer x+18 = -1+18 =17

third integer = x+36 = -1+36=35..

therefore the consecutive integers are -1,17,35..

hope my answer helps you..