Question

three consecutive integers add up to 51
what are the integers​

Answer 1

Let the first number be x. Then as all the three given numbers are consecutive, then the next two numbers will be x + 1 and x + 2. Now, according to the given condition in the question, the three integers add up to 51.

⇒x+x+1+x+2=51

⇒3x+3=51

Taking 3 common, we get,

⇒3(x+1)=51

⇒x+1=513

⇒x+1=17

⇒x=17−1

⇒x=16

So, we have obtained our first number as 16. Then the next numbers are x + 1 and x + 2. Substituting the value of x = 16 in x + 1, we have the second number as 16 + 1 = 17.

Similarly, substituting the value of x = 16 in x + 2, we have the third number as 16 + 2 = 18.

Hence, we have obtained three consecutive numbers as 16, 17 and 18.

Answer 2

Step-by-step explanation:

1 st integer let x

2nd integer be x +1

3rd integer be x+2

( x ) + ( x + 1 ) + ( x + 2 ) = 51

3 x + 3 = 51

3 ( x + 1 ) = 51

x + 1 = 51 ÷ 3

x = 17 - 1

x = 16

now x = 16

x + 1 = 16 + 1 = 17

x + 2 = 16 + 2= 18