Question

three consecutive integers. add up to 51 . what are these integers.​

Answer 1

Answer:

Let the integers be

x,x+1,x+2

x+x+1+x+2=51

3x+3=51

3x=51-3

3x=48

x=16

The three integers are 16,17,18

Answer 2

First Integer = 16

Second Integer = 17

Third Integer = 18

Step-by-step explanation:

Let us assume these integers to be as 'x', 'x + 1', 'x + 2'.

Given that the sum of these numbers = 51

Framing a Linear Equation in one variable adding all these numbers we assumed:

=> x + x + 1 + x + 2  = 51

=> 3x + 3 = 51

Taking 3 to the other side of the equation we get:

=> 3x = 51 - 3

=> 3x = 48

Taking 3 to the other side of the equation we get:

=> x = 48 / 3

=> x = 16

Therefore, the value we obtain for 'x' is 16.

Therefore, the first integer is 16 because we assumed the first integer as 'x'.

Calculating the value of the second integer:

= x  + 1

Putting value of x:

= 16 + 1

= 17

Therefore, the value of the second integer is 17.

Calculating the value of the third integer:

= x + 2

Putting value of x:

= 16 + 2

= 18

Therefore, the value of the third integer is 18.