Question

three consecutive integers add up to 51. what are these three integers

Answer 1

$x, \: x + 1,\: and \: x + 2\: \: are \: three \: consecutive \: integers$

$x + x + 1 + x + 2 = 51$

$3x + 3 = 51$

$3x = 51 - 3$

$3x = 48$

$x = \frac{48}{3}$

$x = 16$

$16, \: 17 ,\: 18\: are \: the \: numbers$

Answer 2

Answer

Let the three consecutive integers be x, x+1 and x+2.

According to the question, x+x+1+x+2=51

\Rightarrow3x+2=51⇒3x+2=51

\Rightarrow3x+3-3=51-3⇒3x+3−3=51−3

[Subtracting 3 from both sides]

\Rightarrow3x=48⇒3x=48

\Rightarrow\ \frac{3x}{3}=\frac{48}{3}⇒

3

3x

=

3

48

[Dividing both sides by 3]

\Rightarrow x=16⇒x=16

Hence, first integer = 16,

second integer = 16 + 1 = 17 and

third integer = 16 + 2 = 18