Question

Three consecutive integers add up to 52. what are the integers.

Answer 1

Let the three numbers be x, x + and x + 2

A/q,

x + x + 1 + x + 2 = 52

3x + 3 = 52

3x = 52 - 3

3x = 49

x = $\frac{49}{3}$

x = $16 \frac{1}{3}$

1st number => $16 \frac{1}{3}$

2nd number => x + 1 = $16 \frac{1}{3} + 1 = 17 \frac{1}{3}$

3rd number => x + 2 = $16 \frac{1}{3} + 2 = 18 \frac{1}{3}$

Answer 2

❤❤here is your answer ✌ ✌

Let ,
the three numbers be x, x + 1and x + 2

A/q,

x + x + 1 + x + 2 = 52

3x + 3 = 52

3x = 52 - 3

3x = 49

x = 49/3
$x = 16 \times \frac{1}{3} \\ x = 16/3 \\ x + 1= 16/3 + 1 = 19/3\\ x + 2= 16/3 + 2 = 22/3$