Question

three consecutive integers add up to 63 find these integers​

Answer 1

Let the first integer be a

Second integer = a + 1

Third integer = a + 2

According to question,

a + a + 1 + a + 2 = 63

=> 3a + 3 = 63

=> 3a = 60

=> a = 20

First integer = 20

Second integer = 21

Third integer = 22

Answer 2

Answer:

let the integers be x , x+1, x+2

ATQ

x+x+1+x+2 = 63

3x+3 = 63

3x= 63 - 3

3x= 60

x = 60/3

x= 20

the integers are

x = 20

x+ 1 = 20+1 = 21

x+ 2 = 20+2 = 22