three consecutive integers add up to 69.what are these integers
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Answered by
20
let the consecutive integers are x,(x+1),(x+3).
A/c to question.
x+(x+1)+(x+2)=69
3x+3=69
3x=69-3
3x=66
x=66/3
x=22
so, the x is 22
and, x+1=22+1=23
x+2=22+1=24.
all of these are consecutive no.
thanks.
A/c to question.
x+(x+1)+(x+2)=69
3x+3=69
3x=69-3
3x=66
x=66/3
x=22
so, the x is 22
and, x+1=22+1=23
x+2=22+1=24.
all of these are consecutive no.
thanks.
ravi572:
thanks again
Answered by
0
Answer:
22,23 and 24
Step-by-step explanation:
Let the three consecutive integers to be x, (x+1), (x+2)
x +(x+1) +(x+2) = 69
3x + 3 = 69
3x = 69 - 3
3x = 66
x = 66/3
x = 22
x = 22
x+1 = 22+1 = 23
x+2 = 22+2 = 24
Thus, the three consecutive integers which add upto 69 are 22,23 and 24 .
HOPE IT HELPS YOU ❤☺
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