Question

three consecutive integers add upto 33 what are these integers
​

Answer 1

Hello mate..

$\huge ❉ \: \underbrace\mathfrak \red{solution : } \: ❉$

Given:

The sum of three consecutive integers is 33.

TO FIND:

The three integers.

SOLUTION:

Let the first integer be ‘x’.

The word consecutive means ’one after the other in order’.

So,

Second integer = x + 1.

Third integer = x + 2.

We know that,

x + x + 1 + x + 2 = 33.

3x + 3 = 33.

3x = 33 - 3.

3x = 30.

$\bold{x = \frac{30}{3} } \\ \bold{ \implies 10}$

x + 1 = 10 + 1

=> 11.

x + 2 = 10 + 2

=> 12.

VERIFICATION: x + x + 1 + x + 2

=> 10 + 11 + 12 = 33.

Therefore, the three consecutive integers are 10, 11, 12.

⠀

HOPE THIS HELPS YOU...

Answer 2

• The three integers are 10, 11 and 12

Given :-

• Three consecutive integers add up to 33.

To find :-

• These three integers.

Step-by-step explanation :-

Since the integers are consecutive,

Therefore let them be x, x + 1 and x + 2 respectively.

They add up to 33.

So, we get :-

$\bf (x) + (x + 1) + (x + 2) = 33$

Removing the brackets,

$\bf x + x + 1 + x + 2 = 33$

Putting all the constants and variables separately,

$\bf x + x + x + 1 + 2 = 33$

On adding,

$\bf 3x + 3 = 33$

Transposing 3 from LHS to RHS, changing its sign,

$\bf 3x = 33 - 3$

On simplifying,

$\bf 3x = 30$

Transposing 3 from LHS to RHS, changing its sign,

$\bf x = \dfrac{30}{3}$

$\bf x = 10.$

The first integer (x) = 10.

So, the other two integers are :-

x + 1 = 10 + 1 = 11.

x + 2 = 10 + 2 = 12.

So, the integers are 10, 11 and 12.

Verification :-

To verify our answer, we just have to find the sum of these three consecutive integers and see whether we get 33 or not.

10 + 11 + 12 = 33.

Since these three consecutive integers add up to 33,

Hence verified!