Question

Three consecutive integers and such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively,they add up to 74.find these numbers.​

Answer 1

Answer:

7,8,9

Step-by-step explanation:

let x be the 1st integer, then (x+1) & (x+2) will be the next consecutive integer.

given (2*x) + (3*(x+1))+ (4*(x+2))= 74

(9*x) + 11= 74

9*x = 63

x = 7

& (x+1) = 8

& (x+2) = 9

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9