Question

Three Consecutive integers are as such they, are taken in increasing order and multiplied by 2,3,and ,4 respectively , they add up to 56. Find these numbers.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The three consecutive integers are: 5, 6, 7

explanation:

First, name the three consecutive integers.

Let's call the first integer:

n

Then the next two integers will be

(n+1) and (n+2)

If we then multiply them as described in the problem and sum these products to 56 we can write an equation as:

2n+3(n+1)+4(n+2)=56

We can now solve this equation for n:

2n+(3×n)+(3×1)+(4×n)+(4×2)=56

2n+3n+4n+3+8=56

3+4n+8=56

2n+3n+4n+3+8=56

(2+3+4)n+(3+8)=56

9n+11=56

9n+11−11=56−11

9n+0=45

9n=45

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