Question

three consecutive integers are as such they are taken in increasing order and multiplied by 2,3and4 respectively they odd up to 56.find these numbers​

Answer 1

Answer:

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Step-by-step explanation:

Let first integer be x

second be x+1

third be x+2

According to the question

If they are multiplied by 2,3,4repectively they add to 56

Therefore 2x+3(x+1) + 4(x+2)=56

2x+3x+4x+3+8=56

9x=45

x=5

So numbers are 5,6,7 respectively

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Answer 2

Answer:

let the there consecutive numbers are x,x+1 and x+2 respectively,

2(x)+3(x+1)+4(x+2)=56

2x+3x+3+4x+8=56

9x+11=56

9x=56-11

9x=45

x=45/9

x=5

Three consecutive numbers are 5,6and 7.