Question

Three consecutive integers are as such they are taken in increasing order and multiplied by
2, 3, and 4, respectively, they add up to 56. Find these numbers.

Answer 1

Answer:

Let's call the first integer: n

Then the next two integers will be (n+1) and (n+2)

If we then multiply them as described in the problem and sum these products to 56 we can write an equation as:

2n+3(n+1)+4(n+2)=56

We can now solve this equation for n:

2n+(3×n)+(3×1)+(4×n)+(4×2)=56

2n+3n+3+4n+8=56

9n+11=56

9n=56-11

9n=45

n=5

n+1=5+1=6

n+2=5+2=7 therefore the numbers are 5,6,7

Answer 2

Answer:

let three consecutive no's are X , x +1 , x +2

now according to question

2(x) + 3(x +1) +4(x +2) =56

2x +3x + 3 + 4x +8 = 56

9 X + 11=56

X = 56-11/9

X = 5

now numbers are

5, 6 , 7

Step-by-step explanation:✔‍