Question

Three consecutive integers are as such they are taken in increasing order and multiplied by 2, 3,
and 4, respectively, they add up to 56. Find these numbers.​

Answer 1

Answer:

5,6 and 7

Step-by-step explanation:

Let the smallest integer of the three consecutive integers be n:

2n + 3(n+1) +4(n+2) = 56

2n + 3n + 3 + 4n + 8 = 56

9n + 11 = 56

9n = 45

n = 5

so the numbers are 5, 6 and 7

Answer 2

Answer:

let the consecutive integers be x-1, x , x+1

2(x-1)+3x+4(x+1)=56

2x-2+3x+4x+4=56

9x+2=56

9x=56-2

9x=54

x=6