Question

Three consecutive integers are as such when they are taken in increasing order and multiplied by 2, 3 & 4 respectively, they add upto 56 Find these numbers​

Answer 1

Answer:

First three consecutive integers= x, x+1, x+2

ATQ,

Increasing order we multiply as= (x)2, (x+1)3, (x+2)4

SO,

(x)2 + (x+1)3 + (x+2)4 = 56

2x + 3x+3 + 4x + 8 = 56

9x + 11 = 56

9x = 56-11

9x = 45

x = 45/9

x = 5

HENCE, numbers are:-

(x)2 = 5*2 = 10

(x+1)3 = (5+1)3 = 18

(x+2)4 = (5+2)4 = 28

Solved