Three consecutive integers are as such when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 56. Find these numbers.
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x
x+1
x+2
2*(x)+3*(x+1)+4*(x+2)=56
9x + 11 = 56
9x = 56-11
9x = 45
x = 45/9
x= 5
Therefore the consecutive numbers are 5, 6 and 7.
Enjoy Math!
Raj
x+1
x+2
2*(x)+3*(x+1)+4*(x+2)=56
9x + 11 = 56
9x = 56-11
9x = 45
x = 45/9
x= 5
Therefore the consecutive numbers are 5, 6 and 7.
Enjoy Math!
Raj
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