Three consecutive integers are as such when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 56. Find these numbers ?
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Answered by
36
let three consecutive no's are X , x +1 , x +2
now according to question
2(x) + 3(x +1) +4(x +2) =56
2x +3x + 3 + 4x +8 = 56
9 X + 11=56
X = 56-11/9
X = 5
now numbers are
5, 6 , 7
now according to question
2(x) + 3(x +1) +4(x +2) =56
2x +3x + 3 + 4x +8 = 56
9 X + 11=56
X = 56-11/9
X = 5
now numbers are
5, 6 , 7
Answered by
1
Answer:
let three consecutive no's are X , x +1 , x +2
now according to question
2(x) + 3(x +1) +4(x +2) =56
2x +3x + 3 + 4x +8 = 56
9 X + 11=56
X = 56-11/9
X = 5
now numbers are
5, 6 , 7
Step-by-step explanation:
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