three consecutive integers are as such when they are taken in increasing order and multiplied by 2 3 and 4 respectively the add up to 56 find these numbers
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let these three consecutive numbers are x,y and z
so Y=x+1,z=Y+1=x+2
A/q,
2x+3Y+3z=56
or,. 2x+3(x+1)+4(x+2)=56
or,. 2x+3x+4x+3+8=56
or,. 9x=56-11
or,. x=45
so Y=x+1,z=Y+1=x+2
A/q,
2x+3Y+3z=56
or,. 2x+3(x+1)+4(x+2)=56
or,. 2x+3x+4x+3+8=56
or,. 9x=56-11
or,. x=45
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