three consecutive integers are such that taken in increasing orderand multiplied by 2,3 and 4 respectively,they add up to 74.Find these numbers
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let first integer =x
second integer =x+1
third integer =x+2
ATQ
2(x)+3(x+1)+4(x+2) = 74
2x+3x+3+4x+8 =74
9x+11 =74
9x=74-11
9x= 63
x= 7
then first integer (x) =7
second integer (x+1) =7+1 =8
third integer (x+2)= 7+2=9
second integer =x+1
third integer =x+2
ATQ
2(x)+3(x+1)+4(x+2) = 74
2x+3x+3+4x+8 =74
9x+11 =74
9x=74-11
9x= 63
x= 7
then first integer (x) =7
second integer (x+1) =7+1 =8
third integer (x+2)= 7+2=9
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