Question

three consecutive integers are such that they are taken in in increasing order and multipled by 2 3 and 4 respectively they are added up to 74 find the integers.
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Answer 1

Answer:

$\huge\underline\bold\red{Answer}$

Let the three consecutive integers be x, x+1, x+2 in increasing order

Multiply 2,3,4 respectively

2(x)+3(x+1)+4(x+2)

This aad up to 74

2(x)+ 3(x + 1) + 4(x + 2) = 74

2x + 3x + 3 + 4x + 8 = 74

9x+11=74

9x=74-11=63

x = 63 ÷ 9

x = 7

Therefore the three consecutive integers are 7,8,9

Answer 2

Answer:

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