Question

three consecutive integers are such that what taken in increasing order and multiplied by 2,3and 4 respectively they add upto 92 find these integers​

Answer 1

Step-by-step explanation:

2x+3x+3+4x+8=92

9x+11=92

9x=81

x=9

therefore the number are 9,10,11

Answer 2

Answer:

9, 10 , 11

Step-by-step explanation:

Let the required integers are 'x' , 'x + 1' and x + 2.

According to the question,

⇒ x multiplied by 2 and  (x + 1) multiplied by 3 and (x + 2) multiplied by 4 = 92

⇒ 2x + 3(x + 1) + 4(x + 2) = 92

⇒ 2x + 3x + 3 + 4x + 8 = 92

⇒ 9x + 11 = 92

⇒ 9x = 92 - 11

⇒ 9x = 81

⇒ x = 81/9 = 9

    Hence the integers are :

x = 9

x + 1 = 9 = 1 = 10

x + 2 = 9 + 2 = 11