three consecutive integers are such that what taken in increasing order and multiplied by 2,3and 4 respectively they add upto 92 find these integers
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Answer:
9, 10 , 11
Step-by-step explanation:
Let the required integers are 'x' , 'x + 1' and x + 2.
According to the question,
⇒ x multiplied by 2 and (x + 1) multiplied by 3 and (x + 2) multiplied by 4 = 92
⇒ 2x + 3(x + 1) + 4(x + 2) = 92
⇒ 2x + 3x + 3 + 4x + 8 = 92
⇒ 9x + 11 = 92
⇒ 9x = 92 - 11
⇒ 9x = 81
⇒ x = 81/9 = 9
Hence the integers are :
x = 9
x + 1 = 9 = 1 = 10
x + 2 = 9 + 2 = 11
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