Three consecutive integers. Are such that when taken in ascending order and multiplied by 2,4 and 6,respectively their sum is 160.find the integers
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Let the three consecutive no. be x,x+1,x+2 in ascending order
Then multiply these no. by 2,4 and 6 respectively
So x(2),x+1(4) and x+2(6)=2x,4x+4,6x+12
Now, there sum is 160
Thus,2x+4x+4+6x+12=160
=>2x+4x+6x+4+12=160
=>12x+16=160
=>12x=160-16=144
=>x=144/12=12
Hence,First no.is 2x=2×12=24,
Second no.is 4x+4=4×12+4=52
And third no. is 6x+12=6×12+12=84
Their sum gives 160.
Then multiply these no. by 2,4 and 6 respectively
So x(2),x+1(4) and x+2(6)=2x,4x+4,6x+12
Now, there sum is 160
Thus,2x+4x+4+6x+12=160
=>2x+4x+6x+4+12=160
=>12x+16=160
=>12x=160-16=144
=>x=144/12=12
Hence,First no.is 2x=2×12=24,
Second no.is 4x+4=4×12+4=52
And third no. is 6x+12=6×12+12=84
Their sum gives 160.
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