Question

three consecutive integers are such that when taken in increasing order multiplied by 2,3 and 4 respectively, they add upto 74. find these numbers
if you are really a math lover than you can tell​

Answer 1

Answer:

Let the, 1st consecutive no. Be x

We have 2(x) + 3(x+1) + 4(x+2) = 74. This leads to 2x + 3x + 3 + 4x + 8 = 74, or 9x + 11 = 74. So, 9x = 63, x = 7. Numbers are 7, 8, and 9.

Answer 2

Answer:

$let \: 1st \: number \: be \: x \\ let \: 2nd \: number \: be \: x + 1 \\ let \: 3rd \: number \: be \: x + 2$

A/Q

2(x)+3(x+1)+4(x+2)=74

2x+3x+3+4x+8=74

9x+11=74

9x=74-11

9x=63

x=63/9

x=7

so 1st number x = 7

2nd number x+1= 7+1= 8

3rd number x+2= 7+2 = 9

hope it helps you Garima✌❤