Three consecutive integers are such that when taken in ascending order and multipled by 2,4, and 6 respectively their sum is 160. Find the integers.
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Answer:
12,13,14
Step-by-step explanation:
let integers are
x-1, x, x+1
these are multiplied respectively by 2,4,6
so intergers will be
2x-2, 4x, 6x+6
according to problem
the sum of integers after multiplying with their respective numbers will be 160
then
2x-2+4x+6x+6=160
12x+4=160
12x=160-4
12x=156
x=156/12
x=13
so first integer will be:
x-1=13-1=12
second integer will be:
x=13
third integer will be:
x+1=13+1=14
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