Three consecutive integers. Are such that when taken in ascending order and multiplied by 2,4 and 6,respectively their sum is 160.find the integers
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Let three consecutive integers be x, x + 1, x + 2.
According to the question,
2x + 3(x + 1) + 6(x + 2) = 160
2x + 3x + 3 +6x+12=160
11x+15=160
11x=145
x=13.18
Numbers are
1-x=13.18
2.x+1=13.18+1=14.18
3.x+2=13.18+2=15.18
According to the question,
2x + 3(x + 1) + 6(x + 2) = 160
2x + 3x + 3 +6x+12=160
11x+15=160
11x=145
x=13.18
Numbers are
1-x=13.18
2.x+1=13.18+1=14.18
3.x+2=13.18+2=15.18
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