Three consecutive integers are such that when taken in ascending order and multiplied by 3,5and 7 respectively, their sum is 244.find the integer
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Answered by
0
Answer:
let the integers be x,x+1,x+2
3(x)+5(x+1)+7(x+2)=244
3x+5x+5+7x+14=244
15x+19=244
15x=225
x=225/15
x=15
x+1=16
x+2=17
the consecutive numbers are 15,16,17
Answered by
139
❍ Let the three integers be x, (x + 1), (x + 2) respectively.
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
- When the three consecutive integers are multipled by 3, 5 and 7, their sum is 244.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Therefore,
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Hence,
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
- First integer = x = 15
- Second integer = (x + 1) = (15 + 1) = 16
- Third integer = (x + 2) = (15 + 2) = 17
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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