Question

three consecutive integers are such that when taken in ascending order and multiplied by 2, 4 and 6 respectively if their sum is 160 find the integers​

Answer 1

Answer:

step by step explanation:-

Given :-

a = -1/2

b = 3/4

1. a × b = b × a

\begin{gathered} = > \: \frac{ - 1}{2} \times \frac{3}{4} \: = \frac{3}{4} \times \frac{-1}{2} \\ \\ = > \: \frac{ - 3}{8} = \frac{ - 3}{8} \\ \\ l.h.s. \: = r.h.s. \\ \\ hence \: proved\end{gathered}

=>

2

−1

×

4

3

=

4

3

×

2

−1

=>

8

−3

=

8

−3

l.h.s.=r.h.s.

henceproved

2. a + b = b + a

\begin{gathered} = > \: \frac{ - 1}{2} + \frac{3}{4} = \frac{3}{4} + \frac{ - 1}{2} \\ \\ l.c.m \: of \: 2 \: and \: 4 = 4 \\ \\ so \\ = > \frac{ - 2 + 3}{4} = \frac{3 - 2}{4} \\ = > \: \frac{1}{4} = \frac{1}{4} \\ \\ \\ l.h.s. = r.h.s. \\ \\ hence \: proved\end{gathered}

=>

2

−1

+

4

3

=

4

3

+

2

−1

l.c.mof2and4=4

so

=>

4

−2+3

=

4

3−2

=>

4

1

=

4

1

l.h.s.=r.h.s.

henceproved

Answer 2

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