Question

three consecutive integers are such that when taken in ascending order the multipled by 2,4 and 6, respectively ,their sum is 160.find the integers.

Answer 1

Let three consecutive integers be x, x + 1, x + 2.

According to the question,

2x + 4(x + 1) + 6(x + 2) = 160

2x + 4x + 4 +6x+12=160

12x+16=160

12x=144

x=144/12

Numbers are

1-x=12

2.x+1=13

3.x+2=14

So, the numbers are 12, 13, 14.

Answer 2

Define x:

Let one number be x.

The other number is (x + 1) and (x + 2).

Form the equation:

2x + 4(x + 1) + 6(x + 2) = 160

2x + 4x + 4 + 6x + 12 = 160

12x + 16 = 160

12x = 144

x = 12

Find the numbers:

first number = x = 12

Second number = x + 2 = 12 + 1 = 13

third number = x + 4 = 12 + 2 = 14

Answer: The numbers are 12, 13 and 14