Question

three consecutive integers are such that when they are written in an a ascending order and multiplied bt 2,,3,and 4 respectively ,they add upto 101 . Find the numbers​

Answer 1

Answer:

Integers are 7,8,9

Step-by-step explanation:

Answer:Three consecutive integers are 7,8 and 9

Solution:

Let the numbers are x, x+1 and x+2

(Since these are consecutive integers)

they are taken in increasing order and multiplied by 2,3 and 4 respectively

So x becomes 2x

(x+1) becomes 3(x+1)

(x+2) becomes 4(x+2)

they add up to 74,so ATQ

So,

Integers are 7,8,9