Question

Three consecutive integers are such that when they are taken in increasing order and multipled by 2,3and4 they add up to 74 find the integers

Answer 1

Answer:

7, 8 and 9

Step-by-step explanation:

Let the 3 consecutive nos. be x-1, x, x+1

And then multiplying these 3 with 2 , 3, 4 respectively we get 74.

The equation is =2(x-1) + 3x +4(x-1) =74

By solving the equation we get x=8.

Answer 2

To Find:

The three consecutive integers which are in such a way that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74.

Solution:

Let us consider the three consecutive integers as $x, \: x+1$ and $x+2$

According to the question,

$2x+3(x+1)+4(x+2)=74\\\implies 2x+3x+3+4x+8=74\\\implies 9x+11=74$

Now, we have to find the value of x,

$9x=74-11\\\implies x=\frac{63}{9} \\:\implies x=7$

Thus, the three consecutive numbers are:

$x=\boxed{7}\\x+1 = \boxed {8}\\x+2 = \boxed{9}$

Therefore the three consecutive numbers are 7, 8 and 9.