Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively they add up to 74, find these numbers​

Answer 1

Answer:

Step-by-step explanation:the numbers are 7,8 and 9

Let the three consecutive integers be x, x+1and x+2. According to the question, 2x+3(x+1)+4(x+2)=74 => 2x+3x+3+4x+8=74 => 9x+11=74 =>9x+11-11=74-11 [Subtracting 11fromboth sides] => 9x=63 => 9x/9=63/9 [Dividing both sides by9] => x=7 Hence first integer = 7, second integer=7 + 1 =8and third integer = 7+ 2= 9.https://www.sarthaks.com/16573/three-consecutive-integers-such-that-when-taken-increasing-order-multiplied-respectively

Answer 2

Answer:

14,24,36,

Step-by-step explanation:

let ,

the first consecutive number=x

the second consecutive number=x+1 and third consecutive number=x+2

now, 2×x, 3 (x+1) and 4 (x+2) =2x,3x+3 and 4x+8

According to the question

2x+3x+3+4x+8=74

9x+11=74

9x=74-11

9x=63

x=63/9

x=7

Now,

2x=2×7=14

3x+3=3×7+3=24

4x+8=4×7+8=36