Question

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2 ,3 and 4 respectively ,they add up to 74 .
find these numbers

Answer 1

Answer:

Step-by-step explanation:

Let us assume three consecutive positive integers are

x, x+1 and x+2

Therefore, as per question 2(x) + 3(x+1) + 4(x+2) = 74

or, 2x + 3x + 3 + 4x + 8 = 74

or, 2x + 3x + 4x + 3 + 8 = 74

or, 9x + 11 = 74

or, 9x = 74 - 11

or, 9x = 63

or, x = 63/9

or, x = 7

Therefore, the numbers are 7, 8 and 9 respectively

Thank you, all the best

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9