Three consecutive integers are such that when they are taken in increasing order and multiplied by 2.3.and 4 respectively they add up to 74 .Find these numbers.
Answers
Answered by
8
Step-by-step explanation:
Let the three consecutive integers be x, x+1and x+2. According to the question, 2x+3(x+1)+4(x+2)=74 => 2x+3x+3+4x+8=74 => 9x+11=74 =>9x+11-11=74-11 [Subtracting 11fromboth sides] => 9x=63 => 9x/9=63/9 [Dividing both sides by9] => x=7 Hence first integer = 7, second integer=7 + 1 =8and third integer = 7+ 2= 9.
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Answered by
3
Answer:
2(x) +3(x+1) +4(x+2) =74
2x +3x+3+4x+8=74
9x=74-11
9x=63
x=7
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