Question

three consecutive integers are such that when they are taken in increasing order and multiplied by 2 3 and 4 respectively they are added to 74 find this number ​

Answer 1

SoluTion :-

Let the numbers are x, x+1 and x+2

$\tt {Since\ these\ are\ consecutive\ integers}$

They are taken in increasing order and multiplied by 2,3 and 4 respectively

$\fbox {So x becomes 2x}\\\\\fbox {(x+1) becomes 3(x+1)}\\\\\fbox {(x+2) becomes 4(x+2)}$

They add up to 74.

So ATQ

$2x + 3(x + 1) + 4(x + 2) = 74 \\ \\ 2x + 3x + 3 + 4x + 8 = 74 \\ \\ 9x + 11 = 74 \\ \\ 9x = 74 - 11 \\ \\ 9x = 63 \\ \\ x = \frac{63}{9} \\ \\ x = 7$

$\fbox {So, Integers are 7,8,9}$

$\rule {130}{2} \ Be \ Brainly \ \star$